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Date(投稿日時):Subject(見出し):From(投稿者):
28982009/06/29Re: (2z+5)/(exp(2z)-1)の留数の求め方は?chiaki@kit.ac.jp (Tsukamoto Chiaki)
28972009/06/29Re: Res_{z=3}(z^4+1)/(z-3)^4を求めたいのですがchiaki@kit.ac.jp (Tsukamoto Chiaki)
28962009/06/29Re: 自己随伴写像AがA=Σ_{j=1}^r α_j E_jとspectral分塊されるなら,α_jは相異なる固有値になる事を示せchiaki@kit.ac.jp (Tsukamoto Chiaki)
28952009/06/29Re: g(z)=1/(z^2(z+3))をz=0を中心にLaurent展開し,収束範囲を求めよchiaki@kit.ac.jp (Tsukamoto Chiaki)
28942009/06/29Re: $B"i (B_C z^{-} dx ( $BC"$7 (B,C $B$O (Bcontour) $B$N@QJ,CM$r5a$a$h (BKyokoYoshida <kyokoyoshida123@gmail.com>
28932009/06/29Re: Res_{z=3}(z^4+1)/(z-3)^4 $B$r5a$a$?$$$N$G$9$, (BKyokoYoshida <kyokoyoshida123@gmail.com>
28922009/06/29Re: g(z)=1/(z^2(z+3)) $B$r (Bz=0 $B$rCf?4$K (BLaurent $BE83+$7 (B, $B<}B+HO0O$r5a$a$h (BKyokoYoshida <kyokoyoshida123@gmail.com>
28912009/06/29Re: (2z+5)/(exp(2z)-1) $B$NN1?t$N5a$aJ}$O (B?KyokoYoshida <kyokoyoshida123@gmail.com>
28902009/06/28自己随伴写像AがA=Σ_{j=1}^r α_j E_jとspectral分塊されるなら,α_jは相異なる固有値になる事を示せKyokoYoshida <kyokoyoshida123@gmail.com>
28892009/06/28Re: ∫_C z^{-} dx (但し,Cはcontour)の積分値を求めよchiaki@kit.ac.jp (Tsukamoto Chiaki)
28882009/06/28Re: Res_{z=3}(z^4+1)/(z-3)^4を求めたいのですがchiaki@kit.ac.jp (Tsukamoto Chiaki)
28872009/06/28Re: (2z+5)/(exp(2z)-1)の留数の求め方は?chiaki@kit.ac.jp (Tsukamoto Chiaki)
28862009/06/28Re: g(z)=1/(z^2(z+3))をz=0を中心にLaurent展開し,収束範囲を求めよchiaki@kit.ac.jp (Tsukamoto Chiaki)
28842009/06/27Re: 速算テクtesigana@diary.ocn.ne.jp (tesigana@diary.ocn.ne.jp)
28822009/06/27∫_C z^{-} dx (但し,Cはcontour)の積分値を求めよKyokoYoshida <kyokoyoshida123@gmail.com>
28812009/06/27Res_{z=3}(z^4+1)/(z-3)^4を求めたいのですがKyokoYoshida <kyokoyoshida123@gmail.com>
28802009/06/27Re: g(z)=1/(z^2(z+3)) $B$r (Bz=0 $B$rCf?4$K (BLaurent $BE83+$7 (B, $B<}B+HO0O$r5a$a$h (BKyokoYoshida <kyokoyoshida123@gmail.com>
28792009/06/27Re: (2z+5)/(exp(2z)-1) $B$NN1?t$N5a$aJ}$O (B?KyokoYoshida <kyokoyoshida123@gmail.com>
28782009/06/26Re: (2z+5)/(exp(2z)-1)の留数の求め方は?chiaki@kit.ac.jp (Tsukamoto Chiaki)
28772009/06/26Re: g(z)=1/(z^2(z+3))をz=0を中心にLaurent展開し,収束範囲を求めよchiaki@kit.ac.jp (Tsukamoto Chiaki)
28762009/06/26Re: g(z)=1/(z^2(z+3)) $B$r (Bz=0 $B$rCf?4$K (BLaurent $BE83+$7 (B, $B<}B+HO0O$r5a$a$h (BKyokoYoshida <kyokoyoshida123@gmail.com>
28752009/06/26Re: (2z+5)/(exp(2z)-1) $B$NN1?t$N5a$aJ}$O (B?KyokoYoshida <kyokoyoshida123@gmail.com>
28732009/06/24Re: (2z+5)/(exp(2z)-1)の留数の求め方は?chiaki@kit.ac.jp (Tsukamoto Chiaki)
28722009/06/24Re: g(z)=1/(z^2(z+3))をz=0を中心にLaurent展開し,収束範囲を求めよchiaki@kit.ac.jp (Tsukamoto Chiaki)
28712009/06/24Re: g(z)=1/(z^2(z+3)) $B$r (Bz=0 $B$rCf?4$K (BLaurent $BE83+$7 (B, $B<}B+HO0O$r5a$a$h (BKyokoYoshida <kyokoyoshida123@gmail.com>
28702009/06/24(2z+5)/(exp(2z)-1)の留数の求め方は?KyokoYoshida <kyokoyoshida123@gmail.com>
28692009/06/24Re: g(z)=1/(z^2(z+3)) $B$r (Bz=0 $B$rCf?4$K (BLaurent $BE83+$7 (B, $B<}B+HO0O$r5a$a$h (BKyokoYoshida <kyokoyoshida123@gmail.com>
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