Re: Gradient of potential function of dynamic field
selftrans@yandex.ru (Sergey Karavashkin) wrote in message news:<a42650fc.0402011435.6e84feaa@posting.google.com>...
> Dear Colleagues,
>
> We open the new volume
> 4 (2004), issue 1
> of our journal
> "SELF Transactions",
> publishing a new paper
>
> " On gradient of potential function of dynamic field "
>
> *Abstract*
>
> We study the gradient of potential function of dynamic field and show
> that in dynamic fields the gradient of function divides into
> coordinate-dependent and time-dependent parts. We will show the
> standard expression connecting the electric field strength with vector
> and scalar potentials to be the consequence of this division of
> gradient in dynamic fields. Due to this, curl of gradient of potential
> function is not zero.
>
> Please enjoy reading full text:
>
> http://angelfire.lycos.com/la3/selftrans/v4_1/contents4.html#grad
>
> I hope, it will be interesting for many of you, and look forward to
> hear your opinion.
>
> Sergey.
There seems to be a mistake on the first page, where you have a scalar
function dependent on both the radial coordinate and angle theta. But
when you take the gradient, you only have a radial component but no
angular one. This is why you're concluding that curl grad is not
zero, when, once you do it properly, it must be. Curl grad must
always vanish regardless of the nature of the coordinate system. It's
an elementary theorem of vector calculus. I hope this has been
helpful. Good luck.
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