Re: Solution to a Pentic
"Jon" <jon8338@peoplepc.com> wrote in message
news:Ns6dne_eNZ5zdYTWnZ2dnUVZ_oydnZ2d@earthlink.com...
> Solution to a pentic:
>
> http://jons-math.bravehost.com/penticsoln.html
>
> This shows the steps to derive the formula below.
>
> The root to ax^5+bx+c=0 is,
>
> x = { -c*({a^2+b^2}^(1/2)+a)/(b^2+a*{a^2+b^2}^(1/2)) }^(1/5)
>
> Using this formula, the roots to,
>
> x^5+x-34=0 x=1.888 should be 2
> 32x^5+4x-3=0 x=0.623 should be 1/2
> x^5+x-0.10001 x=0.5887 should be 1/10
>
>
>
So the formula must be wrong.
Don't believe everything you read on the internet.
Fnews-brouse 1.9(20180406) -- by Mizuno, MWE <mwe@ccsf.jp>
GnuPG Key ID = ECC8A735
GnuPG Key fingerprint = 9BE6 B9E9 55A5 A499 CD51 946E 9BDC 7870 ECC8 A735