isr...@math.ubc.ca (Robert Israel) writes on Feb 4, 2:39 pm

RI> 1/2 I Pi (-1 + erfc(1/2 I))-1/4 hypergeom([1, 1],[3/2,2],1/4)

RI> Is that exact enough for you?


Thank you a lot - your exactness is *absolute*. It is also most
inspiring to see your lightning-like answer you posted in just
25 minutes! Too trivial for you. Okay.

With a serene look, I continue, What then about the following
integral

int(erf(z)*exp(z^2-z^4), z= 0..infinity);

?

If you would not be able to get to the answer here, Is there a
person who can find the exact value of this integral?


Best wishes,

Vladimir Bondarenko

GEMM architect
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